Optimal. Leaf size=297 \[ \frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {sech}^{-1}(c x)\right )}{5 e}-\frac {b d^{5/2} \sqrt {\frac {1}{c x+1}} \sqrt {c x+1} \tanh ^{-1}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {1-c^2 x^2}}\right )}{5 e}-\frac {b \sqrt {\frac {1}{c x+1}} \sqrt {c x+1} \sqrt {1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{20 c^2}-\frac {b \sqrt {\frac {1}{c x+1}} \sqrt {c x+1} \sqrt {1-c^2 x^2} \left (7 c^2 d+3 e\right ) \sqrt {d+e x^2}}{40 c^4}-\frac {b \sqrt {\frac {1}{c x+1}} \sqrt {c x+1} \left (15 c^4 d^2+10 c^2 d e+3 e^2\right ) \tan ^{-1}\left (\frac {\sqrt {e} \sqrt {1-c^2 x^2}}{c \sqrt {d+e x^2}}\right )}{40 c^5 \sqrt {e}} \]
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Rubi [A] time = 0.43, antiderivative size = 297, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 11, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.524, Rules used = {6299, 517, 446, 102, 154, 157, 63, 217, 203, 93, 207} \[ \frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {sech}^{-1}(c x)\right )}{5 e}-\frac {b \sqrt {\frac {1}{c x+1}} \sqrt {c x+1} \left (15 c^4 d^2+10 c^2 d e+3 e^2\right ) \tan ^{-1}\left (\frac {\sqrt {e} \sqrt {1-c^2 x^2}}{c \sqrt {d+e x^2}}\right )}{40 c^5 \sqrt {e}}-\frac {b d^{5/2} \sqrt {\frac {1}{c x+1}} \sqrt {c x+1} \tanh ^{-1}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {1-c^2 x^2}}\right )}{5 e}-\frac {b \sqrt {\frac {1}{c x+1}} \sqrt {c x+1} \sqrt {1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{20 c^2}-\frac {b \sqrt {\frac {1}{c x+1}} \sqrt {c x+1} \sqrt {1-c^2 x^2} \left (7 c^2 d+3 e\right ) \sqrt {d+e x^2}}{40 c^4} \]
Antiderivative was successfully verified.
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Rule 63
Rule 93
Rule 102
Rule 154
Rule 157
Rule 203
Rule 207
Rule 217
Rule 446
Rule 517
Rule 6299
Rubi steps
\begin {align*} \int x \left (d+e x^2\right )^{3/2} \left (a+b \text {sech}^{-1}(c x)\right ) \, dx &=\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {sech}^{-1}(c x)\right )}{5 e}+\frac {\left (b \sqrt {\frac {1}{1+c x}} \sqrt {1+c x}\right ) \int \frac {\left (d+e x^2\right )^{5/2}}{x \sqrt {1-c x} \sqrt {1+c x}} \, dx}{5 e}\\ &=\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {sech}^{-1}(c x)\right )}{5 e}+\frac {\left (b \sqrt {\frac {1}{1+c x}} \sqrt {1+c x}\right ) \int \frac {\left (d+e x^2\right )^{5/2}}{x \sqrt {1-c^2 x^2}} \, dx}{5 e}\\ &=\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {sech}^{-1}(c x)\right )}{5 e}+\frac {\left (b \sqrt {\frac {1}{1+c x}} \sqrt {1+c x}\right ) \operatorname {Subst}\left (\int \frac {(d+e x)^{5/2}}{x \sqrt {1-c^2 x}} \, dx,x,x^2\right )}{10 e}\\ &=-\frac {b \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \sqrt {1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{20 c^2}+\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {sech}^{-1}(c x)\right )}{5 e}-\frac {\left (b \sqrt {\frac {1}{1+c x}} \sqrt {1+c x}\right ) \operatorname {Subst}\left (\int \frac {\sqrt {d+e x} \left (-2 c^2 d^2-\frac {1}{2} e \left (7 c^2 d+3 e\right ) x\right )}{x \sqrt {1-c^2 x}} \, dx,x,x^2\right )}{20 c^2 e}\\ &=-\frac {b \left (7 c^2 d+3 e\right ) \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \sqrt {1-c^2 x^2} \sqrt {d+e x^2}}{40 c^4}-\frac {b \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \sqrt {1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{20 c^2}+\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {sech}^{-1}(c x)\right )}{5 e}+\frac {\left (b \sqrt {\frac {1}{1+c x}} \sqrt {1+c x}\right ) \operatorname {Subst}\left (\int \frac {2 c^4 d^3+\frac {1}{4} e \left (15 c^4 d^2+10 c^2 d e+3 e^2\right ) x}{x \sqrt {1-c^2 x} \sqrt {d+e x}} \, dx,x,x^2\right )}{20 c^4 e}\\ &=-\frac {b \left (7 c^2 d+3 e\right ) \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \sqrt {1-c^2 x^2} \sqrt {d+e x^2}}{40 c^4}-\frac {b \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \sqrt {1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{20 c^2}+\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {sech}^{-1}(c x)\right )}{5 e}+\frac {\left (b d^3 \sqrt {\frac {1}{1+c x}} \sqrt {1+c x}\right ) \operatorname {Subst}\left (\int \frac {1}{x \sqrt {1-c^2 x} \sqrt {d+e x}} \, dx,x,x^2\right )}{10 e}+\frac {\left (b \left (15 c^4 d^2+10 c^2 d e+3 e^2\right ) \sqrt {\frac {1}{1+c x}} \sqrt {1+c x}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {1-c^2 x} \sqrt {d+e x}} \, dx,x,x^2\right )}{80 c^4}\\ &=-\frac {b \left (7 c^2 d+3 e\right ) \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \sqrt {1-c^2 x^2} \sqrt {d+e x^2}}{40 c^4}-\frac {b \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \sqrt {1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{20 c^2}+\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {sech}^{-1}(c x)\right )}{5 e}+\frac {\left (b d^3 \sqrt {\frac {1}{1+c x}} \sqrt {1+c x}\right ) \operatorname {Subst}\left (\int \frac {1}{-d+x^2} \, dx,x,\frac {\sqrt {d+e x^2}}{\sqrt {1-c^2 x^2}}\right )}{5 e}-\frac {\left (b \left (15 c^4 d^2+10 c^2 d e+3 e^2\right ) \sqrt {\frac {1}{1+c x}} \sqrt {1+c x}\right ) \operatorname {Subst}\left (\int \frac {1}{\sqrt {d+\frac {e}{c^2}-\frac {e x^2}{c^2}}} \, dx,x,\sqrt {1-c^2 x^2}\right )}{40 c^6}\\ &=-\frac {b \left (7 c^2 d+3 e\right ) \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \sqrt {1-c^2 x^2} \sqrt {d+e x^2}}{40 c^4}-\frac {b \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \sqrt {1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{20 c^2}+\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {sech}^{-1}(c x)\right )}{5 e}-\frac {b d^{5/2} \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \tanh ^{-1}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {1-c^2 x^2}}\right )}{5 e}-\frac {\left (b \left (15 c^4 d^2+10 c^2 d e+3 e^2\right ) \sqrt {\frac {1}{1+c x}} \sqrt {1+c x}\right ) \operatorname {Subst}\left (\int \frac {1}{1+\frac {e x^2}{c^2}} \, dx,x,\frac {\sqrt {1-c^2 x^2}}{\sqrt {d+e x^2}}\right )}{40 c^6}\\ &=-\frac {b \left (7 c^2 d+3 e\right ) \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \sqrt {1-c^2 x^2} \sqrt {d+e x^2}}{40 c^4}-\frac {b \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \sqrt {1-c^2 x^2} \left (d+e x^2\right )^{3/2}}{20 c^2}+\frac {\left (d+e x^2\right )^{5/2} \left (a+b \text {sech}^{-1}(c x)\right )}{5 e}-\frac {b \left (15 c^4 d^2+10 c^2 d e+3 e^2\right ) \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \tan ^{-1}\left (\frac {\sqrt {e} \sqrt {1-c^2 x^2}}{c \sqrt {d+e x^2}}\right )}{40 c^5 \sqrt {e}}-\frac {b d^{5/2} \sqrt {\frac {1}{1+c x}} \sqrt {1+c x} \tanh ^{-1}\left (\frac {\sqrt {d+e x^2}}{\sqrt {d} \sqrt {1-c^2 x^2}}\right )}{5 e}\\ \end {align*}
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Mathematica [A] time = 1.54, size = 342, normalized size = 1.15 \[ \frac {\sqrt {d+e x^2} \left (8 a c^4 \left (d+e x^2\right )^2+8 b c^4 \text {sech}^{-1}(c x) \left (d+e x^2\right )^2-b e \sqrt {\frac {1-c x}{c x+1}} (c x+1) \left (c^2 \left (9 d+2 e x^2\right )+3 e\right )\right )}{40 c^4 e}+\frac {b \sqrt {\frac {1-c x}{c x+1}} \sqrt {1-c^2 x^2} \left (8 c^7 d^{5/2} \sqrt {-d-e x^2} \tan ^{-1}\left (\frac {\sqrt {d} \sqrt {1-c^2 x^2}}{\sqrt {-d-e x^2}}\right )+\sqrt {-c^2} \sqrt {e} \sqrt {c^2 (-d)-e} \left (15 c^4 d^2+10 c^2 d e+3 e^2\right ) \sqrt {\frac {c^2 \left (d+e x^2\right )}{c^2 d+e}} \sin ^{-1}\left (\frac {c \sqrt {e} \sqrt {1-c^2 x^2}}{\sqrt {-c^2} \sqrt {c^2 (-d)-e}}\right )\right )}{40 c^7 e (c x-1) \sqrt {d+e x^2}} \]
Antiderivative was successfully verified.
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fricas [B] time = 1.57, size = 1667, normalized size = 5.61 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (e x^{2} + d\right )}^{\frac {3}{2}} {\left (b \operatorname {arsech}\left (c x\right ) + a\right )} x\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 2.43, size = 0, normalized size = 0.00 \[ \int x \left (e \,x^{2}+d \right )^{\frac {3}{2}} \left (a +b \,\mathrm {arcsech}\left (c x \right )\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \frac {{\left (e x^{2} + d\right )}^{\frac {5}{2}} a}{5 \, e} + \frac {1}{15} \, b {\left (\frac {{\left ({\left (3 \, e^{2} x^{4} + d e x^{2} - 2 \, d^{2}\right )} x^{3} + 5 \, {\left (d e x^{4} + d^{2} x^{2}\right )} x\right )} \sqrt {e x^{2} + d} \log \left (\sqrt {c x + 1} \sqrt {-c x + 1} + 1\right )}{e x^{3}} - 15 \, \int \frac {{\left (15 \, {\left (c^{2} e^{2} x^{4} \log \relax (c) - e^{2} x^{2} \log \relax (c)\right )} x^{3} + 15 \, {\left (c^{2} d e x^{4} \log \relax (c) - d e x^{2} \log \relax (c)\right )} x + {\left ({\left (3 \, {\left (5 \, e^{2} \log \relax (c) + e^{2}\right )} c^{2} x^{4} - 2 \, c^{2} d^{2} + {\left (c^{2} d e - 15 \, e^{2} \log \relax (c)\right )} x^{2}\right )} x^{3} + 5 \, {\left ({\left (3 \, d e \log \relax (c) + d e\right )} c^{2} x^{4} + {\left (c^{2} d^{2} - 3 \, d e \log \relax (c)\right )} x^{2}\right )} x + 30 \, {\left ({\left (c^{2} e^{2} x^{4} - e^{2} x^{2}\right )} x^{3} + {\left (c^{2} d e x^{4} - d e x^{2}\right )} x\right )} \log \left (\sqrt {x}\right )\right )} e^{\left (\frac {1}{2} \, \log \left (c x + 1\right ) + \frac {1}{2} \, \log \left (-c x + 1\right )\right )} + 30 \, {\left ({\left (c^{2} e^{2} x^{4} - e^{2} x^{2}\right )} x^{3} + {\left (c^{2} d e x^{4} - d e x^{2}\right )} x\right )} \log \left (\sqrt {x}\right )\right )} \sqrt {e x^{2} + d}}{15 \, {\left (c^{2} e x^{4} - e x^{2} + {\left (c^{2} e x^{4} - e x^{2}\right )} e^{\left (\frac {1}{2} \, \log \left (c x + 1\right ) + \frac {1}{2} \, \log \left (-c x + 1\right )\right )}\right )}}\,{d x}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int x\,{\left (e\,x^2+d\right )}^{3/2}\,\left (a+b\,\mathrm {acosh}\left (\frac {1}{c\,x}\right )\right ) \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int x \left (a + b \operatorname {asech}{\left (c x \right )}\right ) \left (d + e x^{2}\right )^{\frac {3}{2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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